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1022. 宠物小精灵之收服

来源：萌宠菠菠乐园时间：2024-11-17 14:46

Link

文章目录题意思路代码

题意

略

思路

https://www.acwing.com/solution/content/117213/

第一问为二维背包模板

n, V, M = IO.read() dp = Arr.array2d(0, V + 1, M + 1) for i in range(n): v, m, w = IO.read() for j in range(V, v - 1, - 1): for k in range(M, m - 1, -1): dp[j][k] = Math.min(dp[j][k], dp[j - v][k - m] + w) print(dp[V][M]) 12345678910 第二问为求剩余体力最大多少，那就是找二维数组的最后，有多少和f[N][M]相同的数

代码

''' Author: NEFU AB-IN Date: 2024-08-15 23:21:56 FilePath: Acwing10221022.py LastEditTime: 2024-08-15 23:22:02 ''' # 3.8.19 import import random from collections import Counter, defaultdict, deque from datetime import datetime, timedelta from functools import lru_cache, reduce from heapq import heapify, heappop, heappush, nlargest, nsmallest from itertools import combinations, compress, permutations, starmap, tee from math import ceil, comb, fabs, floor, gcd, hypot, log, perm, sqrt from string import ascii_lowercase, ascii_uppercase from sys import exit, setrecursionlimit, stdin from typing import Any, Callable, Dict, List, Optional, Tuple, TypeVar, Union # Constants TYPE = TypeVar('TYPE') N = int(2e5 + 10) M = int(20) INF = int(1e12) OFFSET = int(100) MOD = int(1e9 + 7) # Set recursion limit setrecursionlimit(int(2e9)) class Arr: array = staticmethod(lambda x=0, size=N: [x() if callable(x) else x for _ in range(size)]) array2d = staticmethod(lambda x=0, rows=N, cols=M: [Arr.array(x, cols) for _ in range(rows)]) graph = staticmethod(lambda size=N: [[] for _ in range(size)]) class Math: max = staticmethod(lambda a, b: a if a > b else b) min = staticmethod(lambda a, b: a if a < b else b) class IO: input = staticmethod(lambda: stdin.readline().rstrip("rn")) read = staticmethod(lambda: map(int, IO.input().split())) read_list = staticmethod(lambda: list(IO.read())) class Std: pass # ————————————————————— Division line —————————————————————— import bisect def dp(N, M, K, balls, blood): f = [[0] * (M + 1) for _ in range(N + 1)] for i in range(K): for j in range(N, balls[i] - 1, -1): for k in range(M, blood[i], - 1): f[j][k] = max(f[j][k], f[j - balls[i]][k - blood[i]] + 1) if f[N][M] == 0 : return 0, M return f[N][M], M - bisect.bisect_left(f[N], f[N][M]) + 1 N, M, K = map(int, stdin.readline().split()) balls, blood = [0] * K, [0] * K for i in range(K): balls[i], blood[i] = map(int, stdin.readline().split()) C, R = dp(N, M, K, balls, blood) print(str(C) + ' ' + str(R))

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