python解决ax^2+bx+c=0

使用IDE为PyCharm

操作如下

说明

  numpy的sqrt可以对正负数进行开方 ，可以处理ax^2+bx+c=0的所有情况，即sqrt 对实数、复数统一处理

from numpy.lib.scimath import sqrt a = int(input()) b = int(input()) c = int(input()) if a == 0: if b == 0 and c ==0: print("There are infinitely many solutions!") else: if b==0: print ("There is no solution") else: print("There is a unique solution x=%g" %(-1*c/b)) else: disc = b*b -4*a*c if disc > 0: x1 = (-b + sqrt(disc)) / 2 / a x2 = (-b - sqrt(disc)) / 2 / a if disc > 0: print("There are two distinct real roots x1=%g and x2=%g" % (x1, x2)) else: print("There are two conjugate roots x1=%g and x2=%g" % (x1, x2)) else: if disc == 0: print("There are two equal real roots x1=x2=%g" % (-1 * b / 2 / a)) else: x1 = (-b + sqrt(disc)) / 2 / a x2 = (-b - sqrt(disc)) / 2 / a print("There are two conjugate roots x1=%s and x2=%s" % (x1, x2))

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